Difference between revisions of "Antisymmetric subspace"
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==Construction== | ==Construction== | ||
| − | The projection $P_{\mathcal{A}}$ onto the antisymmetric subspace can be constructed by averaging the signed permutation operators:<ref>R.B. Griffiths. [http://quantum.phys.cmu.edu/qm2/qmc161.pdf Systems of Identical Particles], ''33-756 Quantum Mechanics II Course Notes'', 2011.</ref> | + | The [[orthogonal projection]] $P_{\mathcal{A}}$ onto the antisymmetric subspace can be constructed by averaging the signed permutation operators:<ref>R.B. Griffiths. [http://quantum.phys.cmu.edu/qm2/qmc161.pdf Systems of Identical Particles], ''33-756 Quantum Mechanics II Course Notes'', 2011.</ref> |
: $\displaystyle P_{\mathcal{A}} = \frac{1}{p!}\sum_{\sigma \in S_p} (-1)^{{\rm sgn}(\sigma)}P_\sigma$. | : $\displaystyle P_{\mathcal{A}} = \frac{1}{p!}\sum_{\sigma \in S_p} (-1)^{{\rm sgn}(\sigma)}P_\sigma$. | ||
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| + | In the p = 2 case, this reduces to simply $P_{\mathcal{A}} = \frac{1}{2}(I - S)$, where $I$ is the identity operator and $S$ is the bipartite [[swap operator]]. Alternatively, we also have $P_{\mathcal{A}} = I - P_{\mathcal{S}}$ in this case (but not when $p > 2$), where $P_{\mathcal{S}}$ is the orthogonal projection onto the [[symmetric subspace]]. | ||
In order to explicitly construct an orthonormal basis of the antisymmetric subspace, first fix an orthonormal basis $\{|i\rangle\}_{i=1}^d$ of $\mathbb{C}^d$. Now let $q$ be an increasing vector with $p$ entries containing distinct elements of $\{1, 2, \ldots, d\}$ as its entries. Then define | In order to explicitly construct an orthonormal basis of the antisymmetric subspace, first fix an orthonormal basis $\{|i\rangle\}_{i=1}^d$ of $\mathbb{C}^d$. Now let $q$ be an increasing vector with $p$ entries containing distinct elements of $\{1, 2, \ldots, d\}$ as its entries. Then define | ||
: $\displaystyle \mathbf{v}_q \triangleq \frac{1}{\sqrt{p!}}\sum_{\sigma \in S_p} (-1)^{{\rm sgn}(\sigma)} P_\sigma (| q_1 \rangle \otimes \cdots \otimes | q_p \rangle)$. | : $\displaystyle \mathbf{v}_q \triangleq \frac{1}{\sqrt{p!}}\sum_{\sigma \in S_p} (-1)^{{\rm sgn}(\sigma)} P_\sigma (| q_1 \rangle \otimes \cdots \otimes | q_p \rangle)$. | ||
| − | It is then the case that if $q$ ranges over all $\binom{d}{p}$ possible vectors $ | + | It is then the case that $\{\mathbf{v}_q\}_q$ is an orthonormal basis of $\mathcal{A}_p^d$ if $q$ ranges over all $\binom{d}{p}$ possible increasing vectors with $p$ distinct entries chosen from $\{1, 2, \ldots, d\}$. |
==Facts== | ==Facts== | ||
* The dimension of the antisymmetric subspace is $\binom{d}{p}$. It follows that the antisymmetric subspace only has nonzero dimension when d ≥ p. When p = 2, the dimension of the antisymmetric subspace is d(d-1)/2, from which it follows that the symmetric and antisymmetric subspaces span the whole space in this case (and this case only): $\mathcal{A}_2^d \oplus \mathcal{S}_2^d \cong \mathbb{C}^d \otimes \mathbb{C}^d$. | * The dimension of the antisymmetric subspace is $\binom{d}{p}$. It follows that the antisymmetric subspace only has nonzero dimension when d ≥ p. When p = 2, the dimension of the antisymmetric subspace is d(d-1)/2, from which it follows that the symmetric and antisymmetric subspaces span the whole space in this case (and this case only): $\mathcal{A}_2^d \oplus \mathcal{S}_2^d \cong \mathbb{C}^d \otimes \mathbb{C}^d$. | ||
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| + | ==Related [[QETLAB]] functions== | ||
| + | * <tt>[[AntisymmetricProjection]]</tt>: Produces the [[projection]] onto the antisymmetric subspace $P_{\mathcal{A}}$ | ||
| + | * <tt>[[PermutationOperator]]</tt>: Produces a permutation operator $P_\sigma$ | ||
==See also== | ==See also== | ||
* [[Symmetric subspace]] | * [[Symmetric subspace]] | ||
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==References== | ==References== | ||
<references /> | <references /> | ||
Latest revision as of 03:27, 22 November 2012
The antisymmetric subspace $\mathcal{A}_p^d$ is the subspace of $(\mathbb{C}^d)^{\otimes p}$ of all vectors that are negated by odd permutations:
- $\displaystyle \mathcal{A}_p^d \triangleq \big\{ \mathbf{v} \in (\mathbb{C}^d)^{\otimes p} : \mathbf{v} = (-1)^{{\rm sgn}(\sigma)}P_\sigma \mathbf{v} \ \ \forall \sigma \in S_p \big\},$
where $S_p$ is the symmetric group, ${\rm sgn}(\sigma)$ is the parity of the permutation $\sigma$, and $P_\sigma$ is the unitary operator that permutes the $p$ subsystems according to the permutation $\sigma$:
- $\displaystyle P_\sigma(\mathbf{v}_1 \otimes \cdots \otimes \mathbf{v}_p) \triangleq \mathbf{v}_{\sigma(1)} \otimes \cdots \otimes \mathbf{v}_{\sigma(p)}$.
The antisymmetric subspace plays a role quite complementary to that of the symmetric subspace (and indeed, if $\mathcal{S}_p^d$ is the symmetric subspace then $\mathcal{A}_p^d \perp \mathcal{S}_p^d$).
Construction
The orthogonal projection $P_{\mathcal{A}}$ onto the antisymmetric subspace can be constructed by averaging the signed permutation operators:[1]
- $\displaystyle P_{\mathcal{A}} = \frac{1}{p!}\sum_{\sigma \in S_p} (-1)^{{\rm sgn}(\sigma)}P_\sigma$.
In the p = 2 case, this reduces to simply $P_{\mathcal{A}} = \frac{1}{2}(I - S)$, where $I$ is the identity operator and $S$ is the bipartite swap operator. Alternatively, we also have $P_{\mathcal{A}} = I - P_{\mathcal{S}}$ in this case (but not when $p > 2$), where $P_{\mathcal{S}}$ is the orthogonal projection onto the symmetric subspace.
In order to explicitly construct an orthonormal basis of the antisymmetric subspace, first fix an orthonormal basis $\{|i\rangle\}_{i=1}^d$ of $\mathbb{C}^d$. Now let $q$ be an increasing vector with $p$ entries containing distinct elements of $\{1, 2, \ldots, d\}$ as its entries. Then define
- $\displaystyle \mathbf{v}_q \triangleq \frac{1}{\sqrt{p!}}\sum_{\sigma \in S_p} (-1)^{{\rm sgn}(\sigma)} P_\sigma (| q_1 \rangle \otimes \cdots \otimes | q_p \rangle)$.
It is then the case that $\{\mathbf{v}_q\}_q$ is an orthonormal basis of $\mathcal{A}_p^d$ if $q$ ranges over all $\binom{d}{p}$ possible increasing vectors with $p$ distinct entries chosen from $\{1, 2, \ldots, d\}$.
Facts
- The dimension of the antisymmetric subspace is $\binom{d}{p}$. It follows that the antisymmetric subspace only has nonzero dimension when d ≥ p. When p = 2, the dimension of the antisymmetric subspace is d(d-1)/2, from which it follows that the symmetric and antisymmetric subspaces span the whole space in this case (and this case only): $\mathcal{A}_2^d \oplus \mathcal{S}_2^d \cong \mathbb{C}^d \otimes \mathbb{C}^d$.
Related QETLAB functions
- AntisymmetricProjection: Produces the projection onto the antisymmetric subspace $P_{\mathcal{A}}$
- PermutationOperator: Produces a permutation operator $P_\sigma$
See also
References
- ↑ R.B. Griffiths. Systems of Identical Particles, 33-756 Quantum Mechanics II Course Notes, 2011.